The solution of D-E y 2 dy - dx - y 2-1-0 isA- x-y-c tan -1 yB- x-y-c-tan -1 yC- x-y-c-tan -1 yD- y-x-c-tan -1 y

The correct option is B y^2/y^2+1 dy= dx ⇒ x+y=c+tan^ 1y ...

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Linear Differential Equations of First Order

The solution ...

Question

The solution of D.E $y^{2} \frac{d y}{d x} + y^{2} + 1 = 0$ is

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The general solution of the differential equation $\frac{d y}{d x} = \frac{1 + y^{2}}{1 + x^{2}}$ is

(1 + x^{2}) \frac{d y}{d x} + 1 + y^{2} = 0

Solution of the equation $(1 + x^{2}) d y = (1 + y^{2}) d x$ is-

The general solution of $\frac{d y}{d x} + y t a n x = s e c x$ is
(a) y secx=tanx+C
(b) y tanx=secx+C
(c) tanx=y tanx+C
(d) x secx=tany+C

(x + y)^{2} \frac{d y}{d x} = a^{2}, a \neq 0

c

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