Question

The solution of $\frac{2x+3}{2x-1}=\frac{3x-1}{3x+1}$ is

• A. $\frac{1}{8}$
• B. $-\frac{1}{8}$
• C. $\frac{8}{3}$
• D. $-\frac{8}{3}$

Answer 1

The correct option is B $-\frac{1}{8}$

Given that, $\frac{2x+3}{2x-1}=\frac{3x-1}{3x+1}$
By property of dividendo $\frac{2x+3}{(2x+3)-(2x-1)}=\frac{3x-1}{(3x-1)-(3x+1)}$
$\Rightarrow \frac{2x+3}{4}=\frac{3x-1}{-2}$
$\Rightarrow 2x+3=-6x+2$
$\Rightarrow 8x=-1$
$\Rightarrow x=-\frac{1}{8}$