The solution of dydx=2x3y2 is:
ABCD is a parallelogram with vertices A (X1, Y1) , B(X2, Y2) and C (X3, Y3). Then the coordinates of the fourth vertex D in terms of the coordinates of A, B and C are
If ∣∣ ∣∣2a x1 y12b x2 y22c x3 y3∣∣ ∣∣=abc2≠0, then the area of the triangle whose vertices are(x1a,y1a),(x2b,y2b),(x3c,y3c) is