The solution of dydx-ax-hby-k represents a parabola when -

The correct options are A a0,b=0 C a=0,b≠ 0 ...

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Question

The solution of $\frac{d y}{d x} = \frac{a x + h}{b y + k}$ represents a parabola when :

a \neq 0, b = 0

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a = 1, b = 2

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a = 0, b \neq 0

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a = 2, b = 1

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\frac{d y}{d x} = \frac{a x + b}{c y + d}

\frac{d y}{d x} = \frac{a x + b}{c y + d}

\frac{d y}{d x} = (\frac{a x + b}{c y + d})

\frac{d y}{d x} = \frac{a x + b}{c y + d}

\sqrt{\frac{x}{a}} + \sqrt{\frac{y}{b}} = 1

a, b \neq 0

A x^{2} + 2 H x y + B y^{2} + 2 G x + 2 F y + c = 0

Δ \neq 0

H^{2} = A B

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