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Question

The solution of dydx=e2xy+x3ey is:

A
ey=e2x+3x2+c
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B
ey=e2x+x44+c
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C
4ey=2e2x+x4+c
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D
2ey=e2x+3x4+c
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Solution

The correct option is C 4ey=2e2x+x4+c
dydx=e2xey+x3ey
eydy=(e2x+x3)dx
ey=e2x2+x44+c4
4ey=2e2x+x4+c

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