The solution of dydx-elogx is-

The correct option is A 2y=x^2+c dydx=e^log x=x ⇒∫ dy=∫ xdx+c ⇒ y=x^2/2+c ⇒ 2y=x^2+c ...

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Chain Rule of Differentiation

The solution ...

Question

The solution of $\frac{d y}{d x} = e^{l o g x}$ is:

2 y = x^{2} + c

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y = x^{2} + c

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y^{2} = x + c

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x y = x^{2} + c

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