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Question

The solution of differential equation xdydx+2y=x2 is

A
y=x2+C4x2
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B
y=x24+C
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C
y=x4+Cx2
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D
y=x4+C4x2
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Solution

The correct option is D y=x4+C4x2
xdydx+2y=x2
dydx+2xy=x
I.F.=exp(2x dx)=x2
The solution is yx2=xx2 dx
yx2=x44+C1

yx2=x4+4C14

y=x4+C4x2 where C=4C1 is a constant.

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