The solution of differential equation ydx+(x+x2y)dy=0 is:
A
1xy+logy=c
No worries! Weāve got your back. Try BYJUāS free classes today!
B
−1xy+logy=c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
−1xy=c
No worries! Weāve got your back. Try BYJUāS free classes today!
D
xy=logcy
No worries! Weāve got your back. Try BYJUāS free classes today!
Open in App
Solution
The correct option is B−1xy+logy=c ydx+(x+x2y)dy=0⇒ydx+xdy=x2ydy⇒1(xy)2d(xy)=−dyy[ydx+xdy=d(xy)] Integrating both sides, we get −1xy=−logy+c⇒−1xy+logy=c