The solution of dydx=ax+hby+k represent a parabola if:
A
a=2,b=0
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B
a=2,b=2
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C
a=0,b=2
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D
a=0,b=0
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Solution
The correct options are Aa=2,b=0 Ca=0,b=2 y′=ax+hby+k⇒dydx(k+by)=h+ax⇒∫dydx(k+by)dx=∫(h+ax)dx⇒by22+ky=ax22+hx+c Represent parabola only when a=0,b=2 or a=2,b=0