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Question

The solution of x+ax−2a=x+3ax−4a is

A
x=a
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B
x=a2
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C
x=a2
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D
x=a
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Solution

The correct option is B x=a2
x+ax2a=x+3ax4a
(x+a)(x4a)=(x+3a)(x2a)
x2+ax4ax4a2=x2+3ax2ax6a2
3ax4a2=ax6a2
2a2=4ax
x=2a24a =a2

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