Question

The solution of equation $\frac{2\left(m-1\right)+7m}{3m+1}=\frac{2}{3}$ is:

Answer 1

We have,.

$\frac{2\left(m-1\right)+7m}{3m+1}=\frac{2}{3}$

$\frac{2m-2+7m}{3m+1}=\frac{2}{3}$

$\frac{9m-2}{3m+1}=\frac{2}{3}$

$27m-6=6m+2$

$27m-6m=6+2$

$21m=8$

$m=\frac{8}{21}$

Hence, this is the answer.