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Question

The solution of equation dydx=ax+bcy+d represents :

A
A straight line if a=c=0 and b,d0
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B
A parabola if a=2,c=0,d0
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C
A huberbola if b=d=0,a and c0
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D
A rectangular hyberbola of b=d=0,a=c=2
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Solution

The correct option is A A straight line if a=c=0 and b,d0
Given Differential equation is dydx=ax+bcy+d,

Separating the variables and integrating gives,

(cy+d)dy=(ax+b)dx,

cy22+dy=ax22+bx+K,

Where K is the integration constant,

If a=c=0 and b,d0, the equation becomes,

dybx=K which representss a straight line.

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