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Question

The solution of dydx=exy+e2logxy

A
ey=ex+x23+c
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B
ey=ex+x33+c
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C
ey=ex+logx+c
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D
y=e3x+y3
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Solution

The correct option is B ey=ex+x33+c
dydx=exy+e2log xy
eydy=(ex+x2)dx
ey=ex+x3/3+c

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