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Question

The solution of dydx=ax+bcy+d represents a parabola if

A
a = 1, c = 2
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B
a = 0, c = 1
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C
a = 1, c = 1
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D
a = –1, c = 1
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Solution

The correct option is B a = 0, c = 1
(cy+d)dy=(ax+b)dxcy22+dy=ax22+bx+k
It represents a parabola if c=0,a0 or a=0,c0.

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