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Standard IX

Mathematics

Solutions of Linear Equation in 2 Variables on a Graph

The solution ...

Question

The solution of linear equations $3 x - 7 y + 10 = 0$ and $y - 2 x - 3 = 0$ is

x = - 1, y = 1

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x = 1, y = - 1

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x = 1, y = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = - 1, y = - 1

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Solution

The correct option is B $x = - 1, y = 1$
Let $3 x - 7 y + 10 = 0$ --- (1)
and $y - 2 x - 3 = 0$ --- (2)
Multiplying equation $(2)$ with $7$ we get, $7 y - 14 x - 21 = 0$ ----- equation $(3)$
Adding equations $1$ and $3$ , we get $11 x = - 11 => x = - 1$
Substituting
$x = - 1$ in the equation $(2)$ , we get $y - 2 (- 1) - 3 = 0 => y = 1$

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The solution of linear equations 3x−7y+10=0 and y−2x−3=0 is

The correct option is B x=−1,y=1Let 3x−7y+10=0 --- (1) and y−2x−3=0 --- (2)Multiplying equation (2) with 7 we get, 7y−14x−21=0 ----- equation (3)Adding equations 1 and 3, we get 11x=−11=>x=−1Substitutingx=−1 in the equation (2), we get y−2(−1)−3=0=>y=1

The solution of linear equations $3 x - 7 y + 10 = 0$ and $y - 2 x - 3 = 0$ is