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Byju's Answer
Standard IX
Mathematics
Logarithmic Inequalities
The solution ...
Question
The solution of
log
7
log
5
(
√
x
+
5
+
√
x
)
=
0
is __________.
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Solution
x
=
4
, We have
l
o
g
7
l
o
g
5
[
√
x
+
5
+
√
x
]
=
0
⇒
l
o
g
5
[
√
x
+
5
+
√
x
]
=
7
o
=
1
⇒
√
x
+
5
+
√
x
=
5
⇒
√
x
+
5
=
5
−
√
x
⇒
x
+
5
=
25
+
x
−
10
√
x
⇒
2
=
√
x
⇒
x
=
4
.
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Q.
Solution of
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