The solution of pair of linear equations Px - qy - 2P and qx - Py - 2q- P2 - q2 - 0 is equal to- - - - Px - qy - 2P - qx - Py - 2q- P2 - q2 - 0 - - -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Solving Equations Using Method of Substitution

The solution ...

Question

The solution of pair of linear equations Px + qy = 2P and qx + Py = 2q, (P² – q² ≠ 0) is equal to

रैखिक समीकरणों के युग्म Px + qy = 2P व qx + Py = 2q, (P² – q² ≠ 0) का हल है

(2, 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(–2, 0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2, 0)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(0, –2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

p x + q y + λ (q x - p y + r^{'})) = 0

p x + q y - λ (q x - p y + r^{'})) = 0

Three lines $p x + q y + r = 0, q x + r y + p = 0$ and $r x + p y + q = 0$ are concurrent, if

x

y

p x + q y = r

q x - p y = 1 + r

\begin{matrix} p x + q y = p - q q x - p y = p + q \end{matrix}

Join BYJU'S Learning Program