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Question

The solution of primitive equation ydydx=x1y2 is y=y(x), where y(x) is non-constant. If y(0)=1, then which of the following is/are correct

A
y(2)=0
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B
y(314)=±12
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C
y(2 sinθ)=±cos θ θ(0,π)
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D
y(1)=1
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Solution

The correct option is C y(2 sinθ)=±cos θ θ(0,π)
y dy1y2=x dxd(1y2)=xdx1y2=x22+c
Put x=0,y=1c=0
1y2=x44x44+y2=1

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