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Question

The solution of sodium meta aluminate on boiling with ammonium chloride gives a white precipitate of :

A
Al2O3
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B
AlCl3
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C
Al(OH)3
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D
NaAl(OH)4
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Solution

The correct option is D Al(OH)3
The solution of sodium meta aluminate on boiling with ammonium chloride gives a white precipitate of aluminum hydroxide Al(OH)3.
NaAlO2+NH4Cl+H2OAl(OH)3+NaCl+NH3

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