The solution of sodium meta aluminate on boiling with ammonium chloride gives a white precipitate of :
A
Al2O3
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B
AlCl3
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C
Al(OH)3
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D
NaAl(OH)4
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Solution
The correct option is DAl(OH)3 The solution of sodium meta aluminate on boiling with ammonium chloride gives a white precipitate of aluminum hydroxide Al(OH)3. NaAlO2+NH4Cl+H2O→Al(OH)3+NaCl+NH3