The solution of -x4-16-x2-4 is

The correct option is C no solution x = 0 is not a solution as √(16) ≠ 4 ...

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Roots of a Quadratic Equation

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Question

The solution of $\sqrt{x^{4} + 16}$ = $x^{2}$ – 4 is

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-16

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no solution

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Similar questions

The solution of $\sqrt{x^{4} + 16} = x^{2} - 4$ is $x = 0$ .

lim x \to \infty [x \sqrt{x^{2} + 4} - \sqrt{x^{4} + 16}]

x_{1}, x_{2}, x_{3}, x_{4}, x_{5}

\sqrt{x_{1} - 1} + 2 \sqrt{x_{2} - 4} + 3 \sqrt{x_{3} - 9} + 4 \sqrt{x_{4} - 16} + 5 \sqrt{x_{5} - 25} = \frac{x_{1} + x_{2} + x_{3} + x_{4} + x_{5}}{2}

\frac{x_{1} + x_{2} + x_{3} + x_{4} + x_{5}}{2}

The solution of the differential equation $x \frac{d y}{d x} + y = x^{2} + 3 x + 2$ is

x_{1}

x_{2}

x_{1}, x_{2}, x_{3}

x_{4}

2 x_{1}, 2 x_{2} - a, x_{3}, 2 a, x_{4} - a

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