Question

The solution of sulphuric acid 80% by weight sulphuric acid specific gravity of this solution is 1.73 normality is about:

• A. 18
• B. 44.13
• C. 1
• D. 10

Answer 1

The correct option is B 44.13

Given that

Purity of $H_{2}S{O}_4=80$

Specific gravity $=1.73g/ml$

We know that,

Equivalent weight of $H_{2}S{O}_4=\frac{98}{2}=49g-eq$

Now,

We find Normality of $H_{2}S{O}_4$ by given formula,

$=\frac{specificgravity\times 1000}{equivalentweight\times percentpurity}$

Put all given values,

$=\frac{1.73\times 1000}{49\times 0.80}$

$=44.1326N$

This the required solution.