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Question

The solution of the diffeential equaion d2ydx2+dydx+y=0 is

A
Aex+Bex
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B
ex(Ax+B)
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C
ex{Acos(32)x+Bcos(32)x}
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D
ex2{Acos(32)x+Bcos(32)x}
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Solution

The correct option is D ex2{Acos(32)x+Bcos(32)x}
d2ydx2+dydx+y=0
D2 + D + 1 = 0
Auxiliary equation is
m2 + m + 1 = 0
m = 1±3i2
General solution is
y=ex2{Acos(32)x+Bcos(32)x}

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