The solution of the diffeential equaion d2ydx2+dydx+y=0 is
A
Aex+Be−x
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B
ex(Ax+B)
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C
e−x{Acos(√32)x+Bcos(√32)x}
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D
e−x2{Acos(√32)x+Bcos(√32)x}
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Solution
The correct option is De−x2{Acos(√32)x+Bcos(√32)x} d2ydx2+dydx+y=0 D2 + D + 1 = 0
Auxiliary equation is m2 + m + 1 = 0
m = −1±√3i2
General solution is y=e−x2{Acos(√32)x+Bcos(√32)x}