The solution of the differential equation 2xdydxāy=0;y(1)=2 represents _______
A
ellipse
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B
parabola
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C
circle
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D
straight line
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Solution
The correct option is B parabola 2xdydx=y⇒2dyy=dxx Integrating both sides, 2logy=logx+c Given y(1)=2 ⇒2log2=log1+c⇒c=log4 Therefore, logy2=logx+log4 ⇒y2=4x→a parabola