The solution of the differential equation dydx=3e2x+3e4xex+e−x is
A
y=e3x+C
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B
y=2e2x+C
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C
y=ex+C
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D
y=e4x+C
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E
y=9e3x+C
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Solution
The correct option is Dy=e3x+C Given differential equation is dydx=3e2x+3e4xex+e−x=3e2x(1+e2x)⋅ex(1+e2x) ⇒dydx=3⋅e3x ⇒∫dy=∫3⋅e3xdx (on integrating) ⇒y=3⋅e3x3+C ⇒y=e3x+C