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Question

The solution of the differential equation dydx=3e2x+3e4xex+ex is

A
y=e3x+C
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B
y=2e2x+C
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C
y=ex+C
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D
y=e4x+C
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E
y=9e3x+C
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Solution

The correct option is D y=e3x+C
Given differential equation is
dydx=3e2x+3e4xex+ex=3e2x(1+e2x)ex(1+e2x)
dydx=3e3x
dy=3e3xdx (on integrating)
y=3e3x3+C
y=e3x+C

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