21
You visited us
21
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Integrating Factor
The solution ...
Question
The solution of the differential equation
d
y
d
x
=
x
+
y
x
satisfying the condition
y
(
1
)
=
1
is:
A
y
=
x
e
(
x
−
1
)
No worries! Weāve got your back. Try BYJUāS free classes today!
B
y
=
x
l
n
x
+
x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
y
=
l
n
x
+
x
No worries! Weāve got your back. Try BYJUāS free classes today!
D
y
=
x
ln
x
+
x
2
No worries! Weāve got your back. Try BYJUāS free classes today!
Open in App
Solution
The correct option is
B
y
=
x
l
n
x
+
x
d
y
d
x
=
x
+
y
x
Put
y
=
v
x
⇒
d
y
d
x
=
v
+
x
d
v
d
x
⇒
d
v
=
d
x
x
⇒
v
=
log
x
+
c
⇒
y
x
=
log
x
+
c
Since
y
(
1
)
=
1
y
=
x
log
x
+
x
Suggest Corrections
0
Similar questions
Q.
The solution of the differential equation
d
y
d
x
=
x
+
y
x
satisfying the condition
y
(
1
)
=
1
is
Q.
The solution of the differential equation
d
y
d
x
=
x
+
y
x
satisfying the condition
y
(
1
)
=
1
is
Q.
The solution of the differential equation
(
x
+
y
)
2
d
y
d
x
=
1
,
satisfying the condition
y
(
1
)
=
0
, is:
Q.
The solution of differential equation
d
y
d
x
=
−
(
y
+
sin
x
x
)
satisfying condition
y
(
0
)
=
1
, is
Q.
Let
y
be the solution of the differential equation
x
d
y
d
x
=
y
2
1
−
y
log
x
satisfying
y
(
1
)
=
1
. Then
y
satisfies
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Explore more
Integrating Factor
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app