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Question

The solution of the differential equation dydx-ky=0, y0=1 approaches to zero when x → ∞, if
(a) k = 0
(b) k > 0
(c) k < 0
(d) none of these

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Solution

(c) k < 0


We have,dydx-ky=0dydx=ky1ydy=k dxIntegrating both sides, we get1ydy=kdxlogy=kx+C .....1Now, y0=1 C=0Putting C=0 in 1, we getlogy=kxekx=yAccording to the question,ek=0Since e-=0 k<0.

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