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Byju's Answer
Standard XII
Mathematics
Ordinary Differential Equations
The solution ...
Question
The solution of the differential equation
d
y
d
x
-
k
y
=
0
,
y
0
=
1
approaches to zero when x → ∞, if
(a) k = 0
(b) k > 0
(c) k < 0
(d) none of these
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Solution
(c) k < 0
We
have
,
⇒
d
y
d
x
-
k
y
=
0
⇒
d
y
d
x
=
k
y
⇒
1
y
d
y
=
k
d
x
Integrating
both
sides
,
we
get
∫
1
y
d
y
=
k
∫
d
x
⇒
log
y
=
k
x
+
C
.
.
.
.
.
1
Now
,
y
0
=
1
∴
C
=
0
Putting
C
=
0
in
1
,
we
get
log
y
=
k
x
⇒
e
k
x
=
y
According
to
the
question
,
e
k
∞
=
0
Since
e
-
∞
=
0
∴
k
<
0
.
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