The solution of the differential equation d y-d x- x x-tan x is

The correct option is A dy/dx = sec x (sec x + tan x ) ⇒dy/dx = sec^2 x + sec x tan x Now integrating both sides, we get y = tan x + sec x + c. nbsp; ...

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Standard XII

Mathematics

Linear Differential Equations of First Order

The solution ...

Question

The solution of the differential equation $\frac{d y}{d x} = s e c x (s e c x + t a n x)$ is

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Solution

The correct option is A

$\frac{d y}{d x} = s e c x (s e c x + t a n x) \Rightarrow \frac{d y}{d x} = s e c^{2} x + s e c x t a n x$
Now integrating both sides, we get
y = tan x + sec x + c.

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Similar questions

Q. Solution of the differential equation

\frac{d y}{d x} + y sec x = tan x (\leq x < \frac{π}{2})

Q. The general solutions of the differential equation

sin 2 x (\frac{d y}{d x} - \sqrt{t a n x}) - y = 0

For the given differential equation find the general solution.

$c o s^{2} d x \frac{d y}{d x} + y = t a n x (0 \leq x < \frac{p i}{2})$

Q. Show that the solution of the differential equation

\frac{d y}{d x} = 1 + x y^{2} + x + y^{2}, y (0) = 0

y = tan (x + \frac{x^{2}}{2})

Q. Integrating Factor of the differential equation

\frac{d y}{d x} = tan x + e^{x}

______.

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The solution of the differential equation dydx=sec x (sec x+tan x) is

The correct option is A dydx=sec x(sec x+tan x)⇒dydx=sec2 x+sec x tan x Now integrating both sides, we get y = tan x + sec x + c.

The solution of the differential equation $\frac{d y}{d x} = s e c x (s e c x + t a n x)$ is

The correct option is A

$\frac{d y}{d x} = s e c x (s e c x + t a n x) \Rightarrow \frac{d y}{d x} = s e c^{2} x + s e c x t a n x$
Now integrating both sides, we get
y = tan x + sec x + c.