Question

The solution of the differential equation $\frac{dy}{dx}=secx(secx+tanx)$ is

• A. y = sec x + tan x + c.
  
• B. y = sec x + cot x + c.
  
• C. y = sec x - tan x + c
• D. None of these

Answer 1

The correct option is A

y = sec x + tan x + c.

$\frac{dy}{dx}=secx(secx+tanx)\Rightarrow \frac{dy}{dx}=se{c}^{2}x+secxtanx$
Now integrating both sides, we get
y = tan x + sec x + c.