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Question

The solution of the differential equation (xy)(2dydx)=3dx5dy is:

A
2xy=log(xy+z)+c
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B
2x+y=log(xy+z)+c
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C
2yx=log(xy+z)+c
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D
None of these
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Solution

The correct option is C 2yx=log(xy+z)+c
The given equation can be written as
(2x2y+5)dy=(xy+3)dx
dydx=xy+32(xy)+5
Put xy=V1dydx=dVdx
Therefore, the given equation becomes
1dVdx=V+32V+5 dVdx=V+22V+5
dx=2V+5V+2dV dx=(2+1V+2)dV
On integrating, we get x=2V+log(V+2)+c
x=2(xy)+log(xy+2)+c
Therefore, 2yx=log(xy+2)+c, is the required solution.

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