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Question

The solution of the differential equation xdy=⎢ ⎢y+xf(yx)f(yx)⎥ ⎥dx is

A
f(yx)=cx
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B
f(yx)=cy
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C
f(xy)=cx
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D
f(xy)=cx2
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Solution

The correct option is A f(yx)=cx
xdy=⎢ ⎢y+xf(yx)f(yx)⎥ ⎥dx
dydx=yx+f(yx)f(yx)
v+xdvdx=v+f(v)f(v) where v=yx
f(v)f(v)dv=dxx
f(v)=xc (where v=yx
Hence (a) is correct answer.

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