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Question

The solution of the differential equation yxdydx=a(y2+dydx) is

A
y=c(x+a)(1+ay)
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B
y=c(x+a)(1ay)
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C
y=c(xa)(1+ay)
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D
None of these
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Solution

The correct option is B y=c(x+a)(1ay)

yxdydx=a(y2+dydx)yay2=(x+a)dydxdyy(1ay)=dxx+a
On integrating both sides, we get
log ylog(1ay)=log(x+a)+log c
y(1ay)=c(x+a) or c(x+a)(1-ay)=y

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