The solution of the dydx=1xis
y+logx+c=0
y=logx+c
ylogx+c=0
None of these
The explanation for the correct answer.
Find the solution for the given equation:
Given: dydx=1x
Integrate the given equation
⇒∫dydx=∫1xdx⇒y=logx+C∫1xdx=logx+C
Hence option B is the correct answer.