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Byju's Answer
Standard XII
Mathematics
Condition for a Conic to Be a Pair of Straight Lines
The solution ...
Question
The solution of the equation
∣
∣ ∣
∣
x
2
−
1
2
5
x
−
1
2
x
∣
∣ ∣
∣
=
0
are
A
3
,
−
1
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B
−
3
,
1
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C
3
,
1
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D
−
3
,
−
1
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Solution
The correct option is
A
3
,
−
1
Since,
∣
∣ ∣
∣
x
2
−
1
2
5
x
−
1
2
x
∣
∣ ∣
∣
=
0
⇒
∣
∣ ∣
∣
x
2
−
1
2
5
x
−
3
−
3
0
∣
∣ ∣
∣
=
0
R
3
→
R
3
−
R
2
⇒
−
1
(
−
6
+
15
)
−
x
[
−
3
x
+
6
]
=
0
⇒
−
9
+
3
x
2
−
6
x
=
0
⇒
x
2
−
2
x
−
3
=
0
⇒
(
x
−
3
)
(
x
+
1
)
=
0
⇒
x
=
−
1
,
3
Suggest Corrections
0
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Standard XII Mathematics
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