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Question

The solution of the equation dydx=exy+x2 ey is


A

ey=ex+x33+c

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B

ey=ex+2x+c

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C

ey=ex+x3+c

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D

y=ex+c

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Solution

The correct option is A

ey=ex+x33+c


dydx=exy+x2 ey=ey(ex+x2)ey dy=(x2+ex)dx
Now integrating both sides, we
Get ey=x33+ex+c.


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