The solution of the equation given by 2x3+5x+A=0, (where A is a constant) is determined by Newton-Raphson method. First assumption for root of the equation is x0=2 If after one iteration the root obtained is x1=3.5, then the value of A is____
-69.5
Open in App
Solution
The correct option is A -69.5 From Newton Raphson method, x1=x0−f(x0)f′(x0) 3.5=2−2x30+5x0+A6x20+5 1.5=−2(2)3+5(2)+A6(2)2+5 −1.5=16+10+A29 −43.5=26+A A=−69.5