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Question

The solution of the equation [sinx+cosx]1+sin2x=2, πxπ is


A

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B

π

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C

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D

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Solution

The correct option is C


Let I=[sinx+cosx]1+sin2x=[2sin(π4+x)]1+sin2x

At, x=π4,

I=[2sin(π4+π4)]1+sin2π4

=(2)2=2

Here, option (c) is correct.


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