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Question

The solution of the equation log(dydx)=ax+by is

A
ebyb=eaxa+c
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B
ebyb=eaxa+c
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C
ebya=eaxa+c
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D
None of these
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Solution

The correct option is B ebyb=eaxa+c

dydx=eax+by=eaxeby
or ebydy=eaxdx
1beby=1aeax+c

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