The solution of the equation $x + y = 3, 3 x - 2 y = 4$ is

x = 2, y = 1

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x = 1, y = 2

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x = - 2, y = 1

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x = - 2, y = - 1

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Solution

The correct option is C $x = 2, y = 1$
The given equations are
$\Rightarrow x + y = 3 . . . . . . . . (1)$
$\Rightarrow 3 x - 2 y = 4 . . . . . . . . (2)$
Multiply eq (1) by 2
$\Rightarrow 2 x + 2 y = 6 . . . . . . . (3)$
Add eq $(2)$ and eq $(3)$
$\Rightarrow 5 x = 10$
$\Rightarrow x = 2$
put $x = 2$ in eq $(1)$
$\Rightarrow 2 + y = 3$
$\Rightarrow y = 1$
Hence, $x = 2$ and $y = 1$

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