The correct option is C (2,2)
Given: 5x+3y=16 …..(i)
and, 3x+5y=16 …..(ii)
Multiplying (i) by 5, we get
5(5x+3y)=5×16
⇒25x+15y=80 …..(iii)
Multiplying (ii) by 3, we get
3(3x+5y)=3×16
⇒9x+15y=48 …..(iv)
Subtracting (iv) from (iii), we get '
(25x+15y)–(9x+15y)=80–48
⇒16x=32
⇒x=2
Substituting x = 2 in (i), we get
5(2)+3y=16
⇒3y=16−10=6
⇒y=63=2
Thus, (2, 2) is the solution for (i) and (ii).
Hence, the correct answer is option (c).