wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The solution of the equations
3x−y+13=2x+y+25=3x+2y+16 given by

A
x=2,y=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=1,y=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x=1,y=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x=1,y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B x=1,y=1
3xy+13=2x+y+25=3x+2y+16
Now, 3xy+13=2x+y+25
15x5y+5=6x+3y+6
9x8y=1...(1)
2x+y+25=3x+2y+16
12x+6y+12=15x+10y+5
3x+4y=7...(2)
Multiply equation (2) by 2 and add (1)
9x+6x=1+14
15x=15 or x=1
Substitute the value of x in equation (1)
9×18y=1
y=1
Thus, x=y=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon