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Question

The solution of the equations
3x−y+13=2x+y+25=3x+2y+16 given by

A
x=2,y=1
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B
x=1,y=1
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C
x=1,y=1
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D
x=1,y=2
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Solution

The correct option is B x=1,y=1
3xy+13=2x+y+25=3x+2y+16
Now, 3xy+13=2x+y+25
15x5y+5=6x+3y+6
9x8y=1...(1)
2x+y+25=3x+2y+16
12x+6y+12=15x+10y+5
3x+4y=7...(2)
Multiply equation (2) by 2 and add (1)
9x+6x=1+14
15x=15 or x=1
Substitute the value of x in equation (1)
9×18y=1
y=1
Thus, x=y=1

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