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Question

The solution of the following partial differential equation 2ux2=92uy2 is

A
sin(3xy)
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B
3x2+y2
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C
sin(3x3y)
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D
(3y2x2)
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Solution

The correct option is A sin(3xy)
Given DE is
2ux2=92uy2 ... (i)
Let us verify the options
Option (a):u=sin(3xy)
Then ux=3cos(3xy) and 2ux2=9sin(3xy)
uy=cos(3xy) and 2uy2=sin(3xy)
Hence, option (a) satisfies (1)
So it is the required solution.

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