The solution of the pair of linear equations
x+2y=5 and 7x+3y=13 is (2, 1).
False
x+2y=5 ...(1)
7x+3y=13 ...(2)
Let's solve these equations using elimination method.
On multiplying the first equation by 7, we get
7x+14y=35 ...(3)
On subtracting (2) from (3), we have
7x+14y=35
−7x−3y=−13
_______________
11y=22
⇒y=2
On subsituting value of y in x+2y=5, we get
x+2(2)=5
⇒x=1
⇒x=1 and y=2
Hence, the solution of the given equations is (1, 2).