The solution set of $3 x - 4 < 8$ over the set of non-negative square numbers is

{1, 2, 3}

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{1, 4}

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{1}

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{16}

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Solution

The correct option is D ${1}$
$3 x - 4 < 8$
$3 x < 12$
$x < 4$
Hence set of non-negative square numbers belonging to the above set is
${1}$ .

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