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Question

The solution set of (5+4cosθ)(2cosθ+1)=0 in the interval [0,2π] is

A
{π3,2π3}
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B
{π3,π}
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C
{2π3,4π3}
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D
{2π3,5π3}
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Solution

The correct option is D {2π3,4π3}
(5+4cosθ)(2cosθ+1)=0
cosθ=54 (not possible) cosθ=12
cosθ=12
cosθ=cosπ3=cos(π±π3)
θ=2π3,4π3 (II and III quad, cosine is negaitve)

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