Byju's Answer
Standard XII
Mathematics
General Solution of Trigonometric Equation
The solution ...
Question
The solution set of
cos
5
θ
=
−
1
2
is
A
θ
=
2
n
π
5
±
2
π
15
,
n
∈
Z
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B
θ
=
2
n
π
5
±
2
π
3
,
n
∈
Z
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C
θ
=
n
π
5
+
(
−
1
)
n
(
−
π
15
)
,
n
∈
Z
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D
θ
=
2
n
π
±
2
π
3
,
n
∈
Z
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Solution
The correct option is
D
θ
=
2
n
π
5
±
2
π
15
,
n
∈
Z
cos
5
θ
=
−
1
2
⇒
cos
5
θ
=
cos
(
π
−
π
3
)
⇒
cos
5
θ
=
cos
(
2
π
3
)
⇒
5
θ
=
2
n
π
±
2
π
3
⇒
θ
=
2
n
π
5
±
2
π
15
,
n
∈
Z
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