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Question

The solution set of cos5θ=12 is


A
θ=2nπ5±2π15,nZ
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B
θ=2nπ5±2π3,nZ
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C
θ=nπ5+(1)n(π15),nZ
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D
θ=2nπ±2π3,nZ
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Solution

The correct option is D θ=2nπ5±2π15,nZ
cos5θ=12cos5θ=cos(ππ3)cos5θ=cos(2π3)5θ=2nπ±2π3θ=2nπ5±2π15,nZ
 

Mathematics

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