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Method of Intervals

The solution ...

Question

The solution set of $\frac{3}{x + 1} - \frac{2}{x - 1} < 0$ is

A

(- \infty, - 1) \cup (1, 5)

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B

(- 1, 1) \cup (5, \infty)

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C

(- \infty, - 1) \cup (5, \infty)

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D

(- \infty, 5)

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Solution

The correct option is A $(- \infty, - 1) \cup (1, 5)$
$\frac{3}{x + 1} - \frac{2}{x - 1} < 0 \Rightarrow \frac{x - 5}{(x + 1) (x - 1)} < 0$

$∴ x \in (- \infty, - 1) \cup (1, 5)$

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Method of Intervals

Standard XIII Mathematics

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