The solution set of 3 x2-7 x-8-x2-1- 2 is

The correct option is D [1, 6]3x^2 7x +8x^2 +1≤ 2 ⇒ nbsp;3x^2 7x +8x^2 +1 2 ≤ 0 ⇒x^2 7x+6x^2 +1≤ 0 ⇒(x 6)(x 1)x^2 +1≤ 0 ∴ x ∈ [1, 6] ...

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Method of Intervals

The solution ...

Question

The solution set of $\frac{3 x^{2} - 7 x + 8}{x^{2} + 1} \leq 2$ is

[1, 4]

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[1, 2]

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[2, 6]

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[1, 6]

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\frac{3 x^{2} - 7 x + 8}{x^{2} + 1} \leq 2

x

1 < \frac{3 x^{2} - 7 x + 8}{x^{2} + 1} ⩽ 2

\frac{3 x^{2} - x - 2}{x^{2} - 7 x + 12} \div \frac{3 x^{2} - 7 x - 6}{x^{2} - 4}

\frac{3 x^{2} - x - 2}{x^{2} - 7 x + 12} \div \frac{3 x^{2} - 7 x - 6}{x^{2} - 4}

\frac{3 x^{2} - 7 x + 8}{x^{2} + 1} \leq 2

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