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Question

The solution set of secx=sec(π+x) is

A
x=nπ,nZ
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B
x=2nπ±π2,nZ
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C
x=(2n+1)π2,nZ
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D
x=ϕ
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Solution

The correct option is D x=ϕ
secx=sec(π+x)secx=secx2secx=0secx=0
which is not possible as |secx|1

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