The solution set of the in equationx2 - 6x - 7-x - 4- -0 is

Nbsp;(x + 7)(x 1) lt; 0 and x ≠ 4 So x ε nbsp; ( 7,1) ( 4) ...

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Solving Inequalities

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The solution set of the in equation $\frac{x^{2} + 6 x - 7}{| x + 4 |} < 0$ is

( -7, 1)

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(-7, -4)

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$(- 7, - 4) \cup (- 4, 1)$

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$(- 7, - 4) \cup (4, 1)$

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