The solution set of the inequality 4-x+12-7·(2-x)-4<0,for all xbelongs to R, is
(-∞,2)
(-2,∞)
∞,∞
2,∞
Explanation for the correct option:
Solution of in-equality:
4-x+12-7·(2-x)-4<0⇒2-2x+1-7×(2-x)<4⇒22-2x-7×(2-x)-4<0
Let 2-x=t>0
2t2-7t-4<0⇒2t2-8t+t-4<0⇒2t(t-4)+1(t-4)<0⇒(2t+1)(t-4)<0⇒t∈-12,4andt>0⇒0<2-x<4⇒2-x<22⇒-x<2⇒x>-2⇒x∈(-2,∞)
Hence the correct option is option(B)
The value of m for which [{(172)-2}-13]14=7m is:
The term independent of x in the expansion of x+1x23-x13+1-x-1x-x1210, x≠1, is equal to
Arrange 12,13,34, 56 in ascending order.
Evaluate the value of following:-
111+411+311+211
Solve it :-
a-235=-412